Question

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So, the fraction $=yx $

According to the question,

Condition I:

$x+y=2y−3$

$⇒x+y−2y=−3$

$⇒x−y=−3…$(i)

Condition II:

$y−1x−1 =21 $

$⇒2(x−1)=y−1$

$⇒2x−2=y−1$

$⇒2x−y=1…(ii)$

On subtracting Eq.(i) from Eq. (ii), we get

$2x−y−x+y=1+3$

$⇒x=4$

On putting the value of x in Eq. (i), we get

$4−y=−3$

$⇒y=7$

So, the numerator is 4 and the denominator is 7 Hence, the fraction is

$74 $

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