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`g_e = 9.8."m/s"^2`

9.8

The approximate **Acceleration due to Gravity on Earth** is approximately 9.8 m/s^{2}. This approximate value is useful in many simple calculations for students learning the physics of motion. For a more precise value of the acceleration due to gravity, see Acceleration due to Gravity at sea level in SI units described below.

**Acceleration due to Gravity (g)** at sea level on Earth is 9.80665 m/s^{2}.

The formula to compute the acceleration due to gravity is:

`g = G*m_e*m/R_E^2`

Where:

- g is the acceleration due to gravity.
- G is the Universal Gravitational Constant (G)
- M is the mass of the object (e.g. planet)
- R is the distance to the center of mass of the object.

The earth is not a perfect sphere, because of the effect of the Earth's rotation and the resulting centrifugal force has caused the Earth to have a bulge around the equator. The Earth's rotation and the resultant centrifugal force (heading outward) counteracts the effect of gravity (downward). This has a measurable effect in the apparent acceleration due to gravity at different latitudes. A good approximation of the total effect is modeled in the International Gravity Formula below. To indicate the ascension or decline from the equator, latitude (φ) can be used.

The International Gravity Formula, `g(phi) = 9.7803267714*( (1+ 0.00193185138639*sin^2(phi))/sqrt(1- 0.00669437999013* sin^2(phi)))`

Altitude also has an effect on the apparent acceleration due to gravity because of the increased distance from the center of mass. The following equation approximates the acceleration due to gravity as affected by altitude (**h**):

Acceleration due to gravity at different altitudes: `g(h) = g(r_e/(r_e + h))`