# Force on Curved areas

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DavidC.Force on Curved areas
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b3d86153-4469-11e3-a47b-bc764e049c3d

A Hemispherical bowl, radius r, just full of water,  will exert a total force down equal to the sum of all forces acting on the surface.

Total force down = area x pressure intensity at centroid

=2pir^2 *"density of water"*"depth of centroid"*g

= 2pir^2*rho*(r/2)g

=pir^3rhog

But the forces acting around the hemispherical centroid balance out on opposite sides of the vertical axis and:

Resultant Force Down = volume of hemisphere * density of water * g

= 2/3pir^3rhog