Worked Problem Here

Solution

A. The solution contains 4.0 g of NaCl per 100 g of solution. Using the formula mass of NaCl (58.44 g/mol) and the density of the solution (1.02 g/mL), we can calculate the molarity:

MNaCl=moles NaCl/liter solution=(0.07 moles NaCl)/(0.098 L Soln) = 0.70 M Solution

Because 1 mol of NaCl produces 2 mol of particles in solution, the total concentration of dissolved particles in the solution is (2)(0.70 M) = 1.4 M.
B. Now we can use the equation to calculate the osmotic pressure of the solution:

?=MRT=1.4M (0.0821 L*atm/mol*K)(298K) = 34.25 atm = osmotic pressure